What is the answer to (3x-1)/7+(2x-1)/3 =x ?

The answer to (3x-1)/7+(2x-1)/3 =x is x=5

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(3x-1)/7+(2x-1)/3 =x

\frac{3 x - 1}{7} + \frac{2 x - 1}{3} = x

x = 5

Solution steps

\frac{3 x - 1}{7} + \frac{2 x - 1}{3} = x

Multiply by LCM

3 (3 x - 1) + 7 (2 x - 1) = 21 x

Expand

3 (3 x - 1) + 7 (2 x - 1) : 23 x - 10

23 x - 10 = 21 x

Move

10

to the right side

23 x = 21 x + 10

Move

21 x

to the left side

2 x = 10

Divide both sides by

2

x = 5

(3 x - 7)^{2} - 5 (2 x + 1) (x - 2) = - x^{2} - [- (3 x + 1)]

- 2.6 b + 4 = 0.9 b - 17

- 20 = \frac{z}{10} - 22

x, 2 x - y = 12

\frac{2 x + 3}{4} = \frac{x + 7}{3}

What is the answer to (3x-1)/7+(2x-1)/3 =x ?
The answer to (3x-1)/7+(2x-1)/3 =x is x=5
Solve for x: (3x-1)/7+(2x-1)/3 =x
The solution is x=5