What is the answer to (x+4)^2=x(x-14)+5 ?

The answer to (x+4)^2=x(x-14)+5 is x=-1/2

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(x+4)^2=x(x-14)+5

(x + 4)^{2} = x (x - 14) + 5

x = - \frac{1}{2}

Solution steps

(x + 4)^{2} = x (x - 14) + 5

Expand

x (x - 14) : x^{2} - 14 x

x^{2} + 8 x + 16 = x^{2} - 14 x + 5

Expand

(x + 4)^{2} : x^{2} + 8 x + 16

x^{2} + 8 x + 16 = x^{2} - 14 x + 5

Move

16

to the right side

x^{2} + 8 x = x^{2} - 14 x - 11

Subtract

x^{2} - 14 x

from both sides

x^{2} + 8 x - (x^{2} - 14 x) = x^{2} - 14 x - 11 - (x^{2} - 14 x)

Simplify

22 x = - 11

Divide both sides by

22

x = - \frac{1}{2}

12 v + 8 = 3 - 13 v

\frac{x}{4} = \frac{15}{6}

x + 10 = 40

\frac{1}{2} = \frac{2}{2}

x, 3 x - 4 y = - 16

What is the answer to (x+4)^2=x(x-14)+5 ?
The answer to (x+4)^2=x(x-14)+5 is x=-1/2
Solve for x: (x+4)^2=x(x-14)+5
The solution is x=-1/2