What is the answer to (4x-3)/2-(5-2x)/3-(3x-4)/3 =5 ?

The answer to (4x-3)/2-(5-2x)/3-(3x-4)/3 =5 is x= 41/10

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(4x-3)/2-(5-2x)/3-(3x-4)/3 =5

\frac{4 x - 3}{2} - \frac{5 - 2 x}{3} - \frac{3 x - 4}{3} = 5

x = \frac{41}{10}

Solution steps

\frac{4 x - 3}{2} - \frac{5 - 2 x}{3} - \frac{3 x - 4}{3} = 5

Multiply by LCM

3 (4 x - 3) - 2 (- 2 x + 5) - 2 (3 x - 4) = 30

Expand

3 (4 x - 3) - 2 (- 2 x + 5) - 2 (3 x - 4) : 10 x - 11

10 x - 11 = 30

Move

11

to the right side

10 x = 41

Divide both sides by

10

x = \frac{41}{10}

2 + 43 c = c - 13

y, x = y + 3

p - 3 \frac{1}{6} = - 2 \frac{1}{2}

5.4 p + 13.1 = - 2.6 p + 3.5

x, x - 2 y = - 10

What is the answer to (4x-3)/2-(5-2x)/3-(3x-4)/3 =5 ?
The answer to (4x-3)/2-(5-2x)/3-(3x-4)/3 =5 is x= 41/10
Solve for x: (4x-3)/2-(5-2x)/3-(3x-4)/3 =5
The solution is x= 41/10