What is (-sqrt(7)(1+i))/(sqrt(2)+i) ?

The solution to (-sqrt(7)(1+i))/(sqrt(2)+i) is -(sqrt(7)((sqrt(2)+1)+(-1+sqrt(2))i))/3

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simplify (-sqrt(7)(1+i))/(sqrt(2)+i)

simplify

\frac{- 7 ( 1 + i )}{2 + i}

- \frac{7 ( ( 2 + 1 ) + ( - 1 + 2 ) i )}{3}

Solution steps

\frac{- 7 ( 1 + i )}{2 + i}

Multiply by the conjugate

\frac{2 - i}{2 - i}

= \frac{- 7 ( 1 + i ) ( 2 - i )}{( 2 + i ) ( 2 - i )}

Simplify

\frac{- 7 ( 1 + i ) ( 2 - i )}{( 2 + i ) ( 2 - i )} : \frac{- 7 ( ( 2 + 1 ) + ( - 1 + 2 ) i )}{3}

= \frac{- 7 ( ( 2 + 1 ) + ( - 1 + 2 ) i )}{3}

Simplify

\frac{- 7 ( ( 2 + 1 ) + ( - 1 + 2 ) i )}{3} : - \frac{7 ( 2 + 1 + ( - 1 + 2 ) i )}{3}

= - \frac{7 ( 2 + 1 + ( - 1 + 2 ) i )}{3}

Rewrite in standard complex form:

- \frac{7 ( ( 2 + 1 ) + ( - 1 + 2 ) i )}{3}

= - \frac{7 ( ( 2 + 1 ) + ( - 1 + 2 ) i )}{3}

\frac{a ( 1 - 0. 2 ^{4} )}{1 - 0.2} = 671

- 4 (x + 2) > 3 x + 20

x^{2} - 5 x + 2 < 8

(- 25)^{\frac{1}{2}}

\frac{1}{3} (3)^{2}

What is (-sqrt(7)(1+i))/(sqrt(2)+i) ?
The solution to (-sqrt(7)(1+i))/(sqrt(2)+i) is -(sqrt(7)((sqrt(2)+1)+(-1+sqrt(2))i))/3