What is the answer to (x+2)^2=32+(x-2)^2 ?

The answer to (x+2)^2=32+(x-2)^2 is x=4

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(x+2)^2=32+(x-2)^2

(x + 2)^{2} = 32 + (x - 2)^{2}

x = 4

Solution steps

(x + 2)^{2} = 32 + (x - 2)^{2}

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

Expand

32 + (x - 2)^{2} : x^{2} - 4 x + 36

x^{2} + 4 x + 4 = x^{2} - 4 x + 36

Move

4

to the right side

x^{2} + 4 x = x^{2} - 4 x + 32

Subtract

x^{2} - 4 x

from both sides

x^{2} + 4 x - (x^{2} - 4 x) = x^{2} - 4 x + 32 - (x^{2} - 4 x)

Simplify

8 x = 32

Divide both sides by

8

x = 4

- 7 + 4 m = 8 + 4 m + 5 m

x, 3 x + y = - 2

x, 2 x + 2 y = - 18

x, 2 x + 3 y = 14

x, 12 x + 10 y = 90

What is the answer to (x+2)^2=32+(x-2)^2 ?
The answer to (x+2)^2=32+(x-2)^2 is x=4
Solve for x: (x+2)^2=32+(x-2)^2
The solution is x=4