What is the answer to y-(2y+1)=8-(3y+3) ?

The answer to y-(2y+1)=8-(3y+3) is y=3

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y-(2y+1)=8-(3y+3)

y - (2 y + 1) = 8 - (3 y + 3)

y = 3

Solution steps

y - (2 y + 1) = 8 - (3 y + 3)

Expand

y - (2 y + 1) : - y - 1

Expand

8 - (3 y + 3) : - 3 y + 5

- y - 1 = - 3 y + 5

Move

1

to the right side

- y = - 3 y + 6

Move

3 y

to the left side

2 y = 6

Divide both sides by

2

y = 3

\frac{1}{2} + x - \frac{x}{6} = \frac{1}{3} + 16 - \frac{2 x}{9}

x, 4 x - 5 y = 25

x, x - 2 y - 4 = 0

x, 7 x - 15 y = - 2

- \frac{2}{5} h + 1 = 3 - \frac{1}{2} h + \frac{1}{2}

What is the answer to y-(2y+1)=8-(3y+3) ?
The answer to y-(2y+1)=8-(3y+3) is y=3
Solve for y: y-(2y+1)=8-(3y+3)
The solution is y=3