What are the solutions to the equation t^2-3t=0 ?

The solutions to the equation t^2-3t=0 are t=3,t=0

Find the zeros of t^2-3t=0

The zeros of t^2-3t=0 are t=3,t=0

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t^{2} - 3 t = 0

t = 3, t = 0

Solution steps

t^{2} - 3 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

t_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, t_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

t = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

t = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 3, t = 0

3 x + 4 = x + 18

10 x^{2} - 7 x - 12

6 x^{2} - 42 = 0

(1 + \frac{\frac{3.5}{100}}{12})^{3}

380 = - 4.9 t^{2} + 60 t + 380

What are the solutions to the equation t^2-3t=0 ?
The solutions to the equation t^2-3t=0 are t=3,t=0
Find the zeros of t^2-3t=0
The zeros of t^2-3t=0 are t=3,t=0