What is the answer to 2(x-1)(x-2)-3(x+1)=(x-4)(2x-3)+1 ?

The answer to 2(x-1)(x-2)-3(x+1)=(x-4)(2x-3)+1 is x=6

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2(x-1)(x-2)-3(x+1)=(x-4)(2x-3)+1

2 (x - 1) (x - 2) - 3 (x + 1) = (x - 4) (2 x - 3) + 1

x = 6

Solution steps

2 (x - 1) (x - 2) - 3 (x + 1) = (x - 4) (2 x - 3) + 1

Expand

2 (x - 1) (x - 2) - 3 (x + 1) : 2 x^{2} - 9 x + 1

Expand

(x - 4) (2 x - 3) + 1 : 2 x^{2} - 11 x + 13

2 x^{2} - 9 x + 1 = 2 x^{2} - 11 x + 13

Move

1

to the right side

2 x^{2} - 9 x = 2 x^{2} - 11 x + 12

Subtract

2 x^{2} - 11 x

from both sides

2 x^{2} - 9 x - (2 x^{2} - 11 x) = 2 x^{2} - 11 x + 12 - (2 x^{2} - 11 x)

Simplify

2 x = 12

Divide both sides by

2

x = 6

y, x - y = 1

x, 4 x + 2 y = 0

x, 4 x + 4 y = 4

x, 4 x + 2 y = - 18

\frac{x}{4} = - 3

What is the answer to 2(x-1)(x-2)-3(x+1)=(x-4)(2x-3)+1 ?
The answer to 2(x-1)(x-2)-3(x+1)=(x-4)(2x-3)+1 is x=6
Solve for x: 2(x-1)(x-2)-3(x+1)=(x-4)(2x-3)+1
The solution is x=6