What is the answer to (x-4)/3+(x+1)/4+(x-1)/2 =x-1 ?

The answer to (x-4)/3+(x+1)/4+(x-1)/2 =x-1 is x=7

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(x-4)/3+(x+1)/4+(x-1)/2 =x-1

\frac{x - 4}{3} + \frac{x + 1}{4} + \frac{x - 1}{2} = x - 1

x = 7

Solution steps

\frac{x - 4}{3} + \frac{x + 1}{4} + \frac{x - 1}{2} = x - 1

Multiply by LCM

4 (x - 4) + 3 (x + 1) + 6 (x - 1) = 12 x - 12

Expand

4 (x - 4) + 3 (x + 1) + 6 (x - 1) : 13 x - 19

13 x - 19 = 12 x - 12

Move

19

to the right side

13 x = 12 x + 7

Move

12 x

to the left side

x = 7

x, - x + 2 y = 12

11 m + 4 m + 2 m = - 17

x, \frac{x}{3} + \frac{y}{2} = 1

f, f = 3 x^{3} - 2 x^{2} y^{2}

- 2 c = 6 - 3 c

What is the answer to (x-4)/3+(x+1)/4+(x-1)/2 =x-1 ?
The answer to (x-4)/3+(x+1)/4+(x-1)/2 =x-1 is x=7
Solve for x: (x-4)/3+(x+1)/4+(x-1)/2 =x-1
The solution is x=7