What is the answer to solvefor h,hx^2+2x-3=0 ?

The answer to solvefor h,hx^2+2x-3=0 is h=(-2x+3)/(x^2);\quad x\ne 0

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solvefor h,hx^2+2x-3=0

solve for

h, h x^{2} + 2 x - 3 = 0

h = \frac{- 2 x + 3}{x ^{2}}; x \neq = 0

Solution steps

h x^{2} + 2 x - 3 = 0

Move

2 x

to the right side

h x^{2} - 3 = - 2 x

Move

3

to the right side

h x^{2} = - 2 x + 3

Divide both sides by

x^{2}; x \neq = 0

h = \frac{- 2 x + 3}{x ^{2}}; x \neq = 0

x, 5 x + 3 y = 10

x, 4 x + y = - 8

c, 2 x + cos (x) = 0

y, 2 x + 5 y = 10

3 x = 60

What is the answer to solvefor h,hx^2+2x-3=0 ?
The answer to solvefor h,hx^2+2x-3=0 is h=(-2x+3)/(x^2);\quad x\ne 0