What is the answer to 2-(x-1}{40}=\frac{2x-1)/4-(4x-5)/8 ?

The answer to 2-(x-1}{40}=\frac{2x-1)/4-(4x-5)/8 is x=66

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2-(x-1}{40}=\frac{2x-1)/4-(4x-5)/8

2 - \frac{x - 1}{40} = \frac{2 x - 1}{4} - \frac{4 x - 5}{8}

x = 66

Solution steps

2 - \frac{x - 1}{40} = \frac{2 x - 1}{4} - \frac{4 x - 5}{8}

Multiply by LCM

80 - (x - 1) = 10 (2 x - 1) - 5 (4 x - 5)

Expand

80 - (x - 1) : - x + 81

Expand

10 (2 x - 1) - 5 (4 x - 5) : 15

- x + 81 = 15

Move

81

to the right side

- x = - 66

Divide both sides by

- 1

x = 66

\frac{x + 4}{3} + \frac{x + 1}{2} = 6

x, 2 x - 5 y = - 10

- 7 + 3 z = - 2 z + 5 + 8 z

3 x + 80 = 12 x - 1

6 (x + 3) = 2 (5 x - 8)

What is the answer to 2-(x-1}{40}=\frac{2x-1)/4-(4x-5)/8 ?
The answer to 2-(x-1}{40}=\frac{2x-1)/4-(4x-5)/8 is x=66
Solve for x: 2-(x-1}{40}=\frac{2x-1)/4-(4x-5)/8
The solution is x=66