What are the solutions to the equation 5x^2+100x+480=0 ?

The solutions to the equation 5x^2+100x+480=0 are x=-8,x=-12

Find the zeros of 5x^2+100x+480=0

The zeros of 5x^2+100x+480=0 are x=-8,x=-12

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5 x^{2} + 100 x + 480 = 0

x = - 8, x = - 12

Solution steps

5 x^{2} + 100 x + 480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 \cdot 5 \cdot 480}{2 \cdot 5}

10 0^{2} - 4 \cdot 5 \cdot 480 = 20

x_{1, 2} = \frac{- 100 \pm 20}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 100 + 20}{2 \cdot 5}, x_{2} = \frac{- 100 - 20}{2 \cdot 5}

x = \frac{- 100 + 20}{2 \cdot 5} : - 8

x = \frac{- 100 - 20}{2 \cdot 5} : - 12

The solutions to the quadratic equation are:

x = - 8, x = - 12

- 46 x + 23 = 46 x + 23

7 t^{7} - 7 t

25 x^{2} = 16

27 - r^{3}

- \frac{7 π}{4} \cdot \frac{180}{π}

What are the solutions to the equation 5x^2+100x+480=0 ?
The solutions to the equation 5x^2+100x+480=0 are x=-8,x=-12
Find the zeros of 5x^2+100x+480=0
The zeros of 5x^2+100x+480=0 are x=-8,x=-12