What is the answer to solvefor h,S=2pirh+2pir^2 ?

The answer to solvefor h,S=2pirh+2pir^2 is h=(S-2pir^2)/(2pir);\quad r\ne 0

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solvefor h,S=2pirh+2pir^2

solve for

h, S = 2 π r h + 2 π r^{2}

h = \frac{S - 2 π r ^{2}}{2 π r}; r \neq = 0

Solution steps

S = 2 π r h + 2 π r^{2}

Switch sides

2 π r h + 2 π r^{2} = S

Move

2 π r^{2}

to the right side

2 π r h = S - 2 π r^{2}

Divide both sides by

2 π r; r \neq = 0

h = \frac{S - 2 π r ^{2}}{2 π r}; r \neq = 0

4 x - 2 = 8

f, f = {x + 1}

b, a = \frac{1}{2} (a + b) h

10 k - 10 = 5 (3 k + 5)

x, x + y + 1 = 0

What is the answer to solvefor h,S=2pirh+2pir^2 ?
The answer to solvefor h,S=2pirh+2pir^2 is h=(S-2pir^2)/(2pir);\quad r\ne 0