What is the answer to 3x+(2x-3)=7(x-2)-x ?

The answer to 3x+(2x-3)=7(x-2)-x is x=11

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3x+(2x-3)=7(x-2)-x

3 x + (2 x - 3) = 7 (x - 2) - x

x = 11

Solution steps

3 x + (2 x - 3) = 7 (x - 2) - x

Remove parentheses:

(a) = a

3 x + 2 x - 3 = 7 (x - 2) - x

Add similar elements:

3 x + 2 x = 5 x

5 x - 3 = 7 (x - 2) - x

Expand

7 (x - 2) - x : 6 x - 14

5 x - 3 = 6 x - 14

Move

3

to the right side

5 x = 6 x - 11

Move

6 x

to the left side

- x = - 11

Divide both sides by

- 1

x = 11

2 x + 5 = 3

- 17 p - p - 14 p + 11 p - 1 = 20

x, 4 x - 3 y = 5

- 2 x = 14

6 j - 11 j - 11 j + 19 = - 13

What is the answer to 3x+(2x-3)=7(x-2)-x ?
The answer to 3x+(2x-3)=7(x-2)-x is x=11
Solve for x: 3x+(2x-3)=7(x-2)-x
The solution is x=11