What are the solutions to the equation x^2+10x+25=64 ?

The solutions to the equation x^2+10x+25=64 are x=3,x=-13

Find the zeros of x^2+10x+25=64

The zeros of x^2+10x+25=64 are x=3,x=-13

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x^{2} + 10 x + 25 = 64

x = 3, x = - 13

Solution steps

x^{2} + 10 x + 25 = 64

Move

64

to the left side

x^{2} + 10 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 39 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 39) = 16

x_{1, 2} = \frac{- 10 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 16}{2 \cdot 1}, x_{2} = \frac{- 10 - 16}{2 \cdot 1}

x = \frac{- 10 + 16}{2 \cdot 1} : 3

x = \frac{- 10 - 16}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 3, x = - 13

\frac{k - 7}{2} > - 5

22500

t = \frac{- 56}{2 ( - 16 )}

10 \leq y - 27

(- \frac{x}{2 x ^{3}})^{- 2}

What are the solutions to the equation x^2+10x+25=64 ?
The solutions to the equation x^2+10x+25=64 are x=3,x=-13
Find the zeros of x^2+10x+25=64
The zeros of x^2+10x+25=64 are x=3,x=-13