What is the answer to (3x+2)/4-(x+4)/6 =1 ?

The answer to (3x+2)/4-(x+4)/6 =1 is x=2

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(3x+2)/4-(x+4)/6 =1

\frac{3 x + 2}{4} - \frac{x + 4}{6} = 1

x = 2

Solution steps

\frac{3 x + 2}{4} - \frac{x + 4}{6} = 1

Multiply by LCM

3 (3 x + 2) - 2 (x + 4) = 12

Expand

3 (3 x + 2) - 2 (x + 4) : 7 x - 2

7 x - 2 = 12

Move

2

to the right side

7 x = 14

Divide both sides by

7

x = 2

c, - cz + 6 z = t z + 83

x = 1

c = 4.1 \cdot 1 0^{- 3}

a, f = a b^{x}

x, 6 x + 3 y = - 9

What is the answer to (3x+2)/4-(x+4)/6 =1 ?
The answer to (3x+2)/4-(x+4)/6 =1 is x=2
Solve for x: (3x+2)/4-(x+4)/6 =1
The solution is x=2