What is the answer to solvefor a,f=x^2+ax+b ?

The answer to solvefor a,f=x^2+ax+b is a=(f-x^2-b)/x ;\quad x\ne 0

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solvefor a,f=x^2+ax+b

solve for

a, f = x^{2} + a x + b

a = \frac{f - x ^{2} - b}{x}; x \neq = 0

Solution steps

f = x^{2} + a x + b

Switch sides

x^{2} + a x + b = f

Move

x^{2}

to the right side

a x + b = f - x^{2}

Move

b

to the right side

a x = f - x^{2} - b

Divide both sides by

x; x \neq = 0

a = \frac{f - x ^{2} - b}{x}; x \neq = 0

x, (x + m)^{3} - 12 m^{3} = - (x - m)^{3} + 2 x^{3}

7 q - 5 q = 16

- 6 a + 3 = - 3 (2 a - 1)

a x + b = b x - a

y, x = y - 1

What is the answer to solvefor a,f=x^2+ax+b ?
The answer to solvefor a,f=x^2+ax+b is a=(f-x^2-b)/x ;\quad x\ne 0