What are the solutions to the equation x^2+9x-2=0 ?

The solutions to the equation x^2+9x-2=0 are x=(-9+sqrt(89))/2 ,x=(-9-sqrt(89))/2

Find the zeros of x^2+9x-2=0

The zeros of x^2+9x-2=0 are x=(-9+sqrt(89))/2 ,x=(-9-sqrt(89))/2

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x^{2} + 9 x - 2 = 0

x = \frac{- 9 + 89}{2}, x = \frac{- 9 - 89}{2}

Decimal Notation

x = 0.21699 \dots, x = - 9.21699 \dots

Solution steps

x^{2} + 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 2) = 89

x_{1, 2} = \frac{- 9 \pm 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 89}{2 \cdot 1}, x_{2} = \frac{- 9 - 89}{2 \cdot 1}

x = \frac{- 9 + 89}{2 \cdot 1} : \frac{- 9 + 89}{2}

x = \frac{- 9 - 89}{2 \cdot 1} : \frac{- 9 - 89}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 89}{2}, x = \frac{- 9 - 89}{2}

- 5 x \leq - 10

2.25 - 11 j - 7.75 + 1.5 j = 0.5 j - 1

\frac{4.5 \cdot 1 0 ^{3}}{9 \cdot 1 0 ^{7}}

2 \leq x \leq 8

\frac{1}{12} (3 a - 6 b)

What are the solutions to the equation x^2+9x-2=0 ?
The solutions to the equation x^2+9x-2=0 are x=(-9+sqrt(89))/2 ,x=(-9-sqrt(89))/2
Find the zeros of x^2+9x-2=0
The zeros of x^2+9x-2=0 are x=(-9+sqrt(89))/2 ,x=(-9-sqrt(89))/2