What is the answer to solvefor a,(x-a)^2+y^2=a^2 ?

The answer to solvefor a,(x-a)^2+y^2=a^2 is a=-(-x^2-y^2)/(2x);\quad x\ne 0

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solvefor a,(x-a)^2+y^2=a^2

solve for

a, (x - a)^{2} + y^{2} = a^{2}

a = - \frac{- x ^{2} - y ^{2}}{2 x}; x \neq = 0

Solution steps

(x - a)^{2} + y^{2} = a^{2}

Expand

(x - a)^{2} + y^{2} : x^{2} - 2 a x + a^{2} + y^{2}

x^{2} - 2 a x + a^{2} + y^{2} = a^{2}

Move

x^{2}

to the right side

- 2 a x + a^{2} + y^{2} = a^{2} - x^{2}

Move

y^{2}

to the right side

- 2 a x + a^{2} = a^{2} - x^{2} - y^{2}

Move

a^{2}

to the left side

- 2 a x = - x^{2} - y^{2}

Divide both sides by

- 2 x; x \neq = 0

a = - \frac{- x ^{2} - y ^{2}}{2 x}; x \neq = 0

x, (x + y)^{2} = x^{2} + y^{2}

x, - 5 x = 8 - y

3 + v = 2 (2 v - 1)

3 (q - 5) = 2 (q + 5)

8 (3 x + 2) - 3 x = 3 (5 x - 4) - 2

What is the answer to solvefor a,(x-a)^2+y^2=a^2 ?
The answer to solvefor a,(x-a)^2+y^2=a^2 is a=-(-x^2-y^2)/(2x);\quad x\ne 0