What is the answer to solvefor h,S=2pir^2+2pirh ?

The answer to solvefor h,S=2pir^2+2pirh is h=(S-2pir^2)/(2pir);\quad r\ne 0

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solvefor h,S=2pir^2+2pirh

solve for

h, S = 2 π r^{2} + 2 π r h

h = \frac{S - 2 π r ^{2}}{2 π r}; r \neq = 0

Solution steps

S = 2 π r^{2} + 2 π r h

Switch sides

2 π r^{2} + 2 π r h = S

Move

2 π r^{2}

to the right side

2 π r h = S - 2 π r^{2}

Divide both sides by

2 π r; r \neq = 0

h = \frac{S - 2 π r ^{2}}{2 π r}; r \neq = 0

y = lo g_{3} (1)

6 x - 3 - 11 - 8 x = 2

10 t + 4 - 2 t = 2 - 2 (t + 4)

- 5.51 = n + 3.35

3 x - 3 = 4 x + 11

What is the answer to solvefor h,S=2pir^2+2pirh ?
The answer to solvefor h,S=2pir^2+2pirh is h=(S-2pir^2)/(2pir);\quad r\ne 0