What is the answer to solvefor a,x^3+y^3-3axy=0 ?

The answer to solvefor a,x^3+y^3-3axy=0 is a=-(-x^3-y^3)/(3xy);\quad-3xy\ne 0

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solvefor a,x^3+y^3-3axy=0

solve for

a, x^{3} + y^{3} - 3 a x y = 0

a = - \frac{- x ^{3} - y ^{3}}{3 x y}; - 3 x y \neq = 0

Solution steps

x^{3} + y^{3} - 3 a x y = 0

Move

x^{3}

to the right side

y^{3} - 3 a x y = - x^{3}

Move

y^{3}

to the right side

- 3 a x y = - x^{3} - y^{3}

Divide both sides by

- 3 x y; - 3 x y \neq = 0

a = - \frac{- x ^{3} - y ^{3}}{3 x y}; - 3 x y \neq = 0

x, 2 x - y = - 8

x, 2 x - y = - 5

\frac{x + m}{n} - \frac{x - n}{m} = 2

- 4 (5 h + 7) + 16 h = 40

r, 19 x + r x = - 37 x + w

What is the answer to solvefor a,x^3+y^3-3axy=0 ?
The answer to solvefor a,x^3+y^3-3axy=0 is a=-(-x^3-y^3)/(3xy);\quad-3xy\ne 0