What are the solutions to the equation (x+3)(3x-2)=0 ?

The solutions to the equation (x+3)(3x-2)=0 are x=-3,x= 2/3

Find the zeros of (x+3)(3x-2)=0

The zeros of (x+3)(3x-2)=0 are x=-3,x= 2/3

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(x + 3) (3 x - 2) = 0

x = - 3, x = \frac{2}{3}

Decimal Notation

x = - 3, x = 0.66666 \dots

Solution steps

(x + 3) (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or 3 x - 2 = 0

Solve

x + 3 = 0 : x = - 3

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions to the quadratic equation are:

x = - 3, x = \frac{2}{3}

- 8 x - 4 = - 7 x + 2

\frac{1}{6 ^{- 1}}

f = 3 (- 3) - 2

n^{2} - 9 n + 18

4 w^{2} + w = 3

What are the solutions to the equation (x+3)(3x-2)=0 ?
The solutions to the equation (x+3)(3x-2)=0 are x=-3,x= 2/3
Find the zeros of (x+3)(3x-2)=0
The zeros of (x+3)(3x-2)=0 are x=-3,x= 2/3