What is the answer to -3(2x^2+ax+b)=-6x^2+12x-15 ?

The answer to -3(2x^2+ax+b)=-6x^2+12x-15 is x=-(-5+b)/(4+a);\quad a\ne-4

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-3(2x^2+ax+b)=-6x^2+12x-15

- 3 (2 x^{2} + a x + b) = - 6 x^{2} + 12 x - 15

x = - \frac{- 5 + b}{4 + a}; a \neq = - 4

Solution steps

- 3 (2 x^{2} + a x + b) = - 6 x^{2} + 12 x - 15

Expand

- 3 (2 x^{2} + a x + b) : - 6 x^{2} - 3 a x - 3 b

- 6 x^{2} - 3 a x - 3 b = - 6 x^{2} + 12 x - 15

Move

3 b

to the right side

- 6 x^{2} - 3 a x = - 6 x^{2} + 12 x - 15 + 3 b

Subtract

- 6 x^{2} + 12 x

from both sides

- 6 x^{2} - 3 a x - (- 6 x^{2} + 12 x) = - 6 x^{2} + 12 x - 15 + 3 b - (- 6 x^{2} + 12 x)

Simplify

- 3 a x - 12 x = - 15 + 3 b

Factor

- 3 a x - 12 x : - 3 x (a + 4)

- 3 x (a + 4) = - 15 + 3 b

Divide both sides by

- 3 (a + 4); a \neq = - 4

x = - \frac{- 5 + b}{4 + a}; a \neq = - 4

24 x + 71 = x + 2

10 x - 4 x + 6 - 2 = 8 x + 10 - 6 + 6 x

x, 6 x + 3 y = - 12

x, x - 3 y = - 15

x, 2 x - 5 y = 11

What is the answer to -3(2x^2+ax+b)=-6x^2+12x-15 ?
The answer to -3(2x^2+ax+b)=-6x^2+12x-15 is x=-(-5+b)/(4+a);\quad a\ne-4