What is (64x^3y^3z^2)/(24xy^4z^4) ?

The solution to (64x^3y^3z^2)/(24xy^4z^4) is (8x^2)/(3yz^2)

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simplify (64x^3y^3z^2)/(24xy^4z^4)

simplify

\frac{64 x ^{3} y ^{3} z ^{2}}{24 x y ^{4} z ^{4}}

\frac{8 x ^{2}}{3 y z ^{2}}

Solution steps

\frac{64 x ^{3} y ^{3} z ^{2}}{24 x y ^{4} z ^{4}}

Factor the number:

64 = 8 \cdot 8

= \frac{8 \cdot 8 x ^{3} y ^{3} z ^{2}}{24 x y ^{4} z ^{4}}

Factor the number:

24 = 8 \cdot 3

= \frac{8 \cdot 8 x ^{3} y ^{3} z ^{2}}{8 \cdot 3 x y ^{4} z ^{4}}

Cancel the common factor:

8

= \frac{8 x ^{3} y ^{3} z ^{2}}{3 x y ^{4} z ^{4}}

Simplify

\frac{x ^{3}}{x} : x^{2}

= \frac{8 x ^{2} y ^{3} z ^{2}}{3 y ^{4} z ^{4}}

Simplify

\frac{y ^{3}}{y ^{4}} : \frac{1}{y}

= \frac{8 x ^{2} z ^{2}}{3 y z ^{4}}

Simplify

\frac{z ^{2}}{z ^{4}} : \frac{1}{z ^{2}}

= \frac{8 x ^{2}}{3 y z ^{2}}

1 \cdot 5 - \frac{6}{3} \cdot 89

∣ x - 7 ∣ = - 4

6 x^{2} + 7 x - 7 = - 9

(\frac{5}{3})^{1}

x + \frac{2}{3} = 2

What is (64x^3y^3z^2)/(24xy^4z^4) ?
The solution to (64x^3y^3z^2)/(24xy^4z^4) is (8x^2)/(3yz^2)