What is the answer to solvefor x,xy^2+8xy^3+9=0 ?

The answer to solvefor x,xy^2+8xy^3+9=0 is x=-9/(y^2(1+8y));\quad y\ne 0,y\ne-1/8

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solvefor x,xy^2+8xy^3+9=0

solve for

x, x y^{2} + 8 x y^{3} + 9 = 0

x = - \frac{9}{y ^{2} ( 1 + 8 y )}; y \neq = 0, y \neq = - \frac{1}{8}

Solution steps

x y^{2} + 8 x y^{3} + 9 = 0

Move

9

to the right side

x y^{2} + 8 x y^{3} = - 9

Factor

x y^{2} + 8 x y^{3} : x y^{2} (1 + 8 y)

x y^{2} (1 + 8 y) = - 9

Divide both sides by

y^{2} (1 + 8 y); y \neq = 0, y \neq = - \frac{1}{8}

x = - \frac{9}{y ^{2} ( 1 + 8 y )}; y \neq = 0, y \neq = - \frac{1}{8}

2 (2 z - 4) = 4

\frac{4 x - 3}{2} = \frac{5 x + 1}{3}

lo g_{10} (\frac{1}{100000}) = - 5

\frac{2}{5} + \frac{3}{5} n - \frac{11}{5} = \frac{2}{5} n + \frac{1}{5}

5 - \frac{3}{10} z + 2 = \frac{6}{5} z - \frac{1}{2} z + 3

What is the answer to solvefor x,xy^2+8xy^3+9=0 ?
The answer to solvefor x,xy^2+8xy^3+9=0 is x=-9/(y^2(1+8y));\quad y\ne 0,y\ne-1/8