What is the answer to x+2[4-2(x+1)-3(x+3)]-4=x+2 ?

The answer to x+2[4-2(x+1)-3(x+3)]-4=x+2 is x=-2

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x+2[4-2(x+1)-3(x+3)]-4=x+2

x + 2 [4 - 2 (x + 1) - 3 (x + 3)] - 4 = x + 2

x = - 2

Solution steps

x + 2 [4 - 2 (x + 1) - 3 (x + 3)] - 4 = x + 2

Subtract

x

from both sides

x + 2 [4 - 2 (x + 1) - 3 (x + 3)] - 4 - x = x + 2 - x

Simplify

2 [4 - 2 (x + 1) - 3 (x + 3)] - 4 = 2

Move

4

to the right side

2 [4 - 2 (x + 1) - 3 (x + 3)] = 6

Expand

2 (4 - 2 (x + 1) - 3 (x + 3)) : - 10 x - 14

- 10 x - 14 = 6

Move

14

to the right side

- 10 x = 20

Divide both sides by

- 10

x = - 2

x, y - 2 x = 1

lo g_{5} (\frac{1}{625}) = x

y = - 2 + 4

\frac{3}{4} x + \frac{5}{2} = \frac{5}{2} x - \frac{11}{4}

l, P = 2 l + 2 w

What is the answer to x+2[4-2(x+1)-3(x+3)]-4=x+2 ?
The answer to x+2[4-2(x+1)-3(x+3)]-4=x+2 is x=-2
Solve for x: x+2[4-2(x+1)-3(x+3)]-4=x+2
The solution is x=-2