What is the answer to solvefor B,h=D^2(B-5g) ?

The answer to solvefor B,h=D^2(B-5g) is B= h/(D^2)+5g;\quad D\ne 0

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solvefor B,h=D^2(B-5g)

solve for

B, h = D^{2} (B - 5 g)

B = \frac{h}{D ^{2}} + 5 g; D \neq = 0

Solution steps

h = D^{2} (B - 5 g)

Switch sides

D^{2} (B - 5 g) = h

Divide both sides by

D^{2}; D \neq = 0

B - 5 g = \frac{h}{D ^{2}}; D \neq = 0

Move

5 g

to the right side

B = \frac{h}{D ^{2}} + 5 g; D \neq = 0

x, 3 y + 4 x = 3

\frac{1}{2} x - 3 = 2 (\frac{x - 1}{5})

\frac{x - 3}{4} + \frac{x + 2}{3} = 4

3 x + 2 = 3

x, 2 x - 5 y = 8

What is the answer to solvefor B,h=D^2(B-5g) ?
The answer to solvefor B,h=D^2(B-5g) is B= h/(D^2)+5g;\quad D\ne 0