What are the solutions to the equation 5z^2+9z-2=0 ?

The solutions to the equation 5z^2+9z-2=0 are z= 1/5 ,z=-2

Find the zeros of 5z^2+9z-2=0

The zeros of 5z^2+9z-2=0 are z= 1/5 ,z=-2

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5 z^{2} + 9 z - 2 = 0

z = \frac{1}{5}, z = - 2

Solution steps

5 z^{2} + 9 z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 2) = 11

z_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- 9 + 11}{2 \cdot 5}, z_{2} = \frac{- 9 - 11}{2 \cdot 5}

z = \frac{- 9 + 11}{2 \cdot 5} : \frac{1}{5}

z = \frac{- 9 - 11}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

z = \frac{1}{5}, z = - 2

7 (7 x + 8) = 5 (6 x + 7) + 59

3 x^{2} = 6 x - 1

\frac{h}{15} = \frac{16}{3}

7 (3 x - 4) = 49

\frac{∣ 3 x + 1 ∣}{∣ x ∣} \leq 3

What are the solutions to the equation 5z^2+9z-2=0 ?
The solutions to the equation 5z^2+9z-2=0 are z= 1/5 ,z=-2
Find the zeros of 5z^2+9z-2=0
The zeros of 5z^2+9z-2=0 are z= 1/5 ,z=-2