What is the answer to 3^2+(x+1)^2=(x+2)^2 ?

The answer to 3^2+(x+1)^2=(x+2)^2 is x=3

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3^2+(x+1)^2=(x+2)^2

3^{2} + (x + 1)^{2} = (x + 2)^{2}

x = 3

Solution steps

3^{2} + (x + 1)^{2} = (x + 2)^{2}

3^{2} = 9

9 + (x + 1)^{2} = (x + 2)^{2}

Expand

9 + (x + 1)^{2} : x^{2} + 2 x + 10

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

x^{2} + 2 x + 10 = x^{2} + 4 x + 4

Move

10

to the right side

x^{2} + 2 x = x^{2} + 4 x - 6

Subtract

x^{2} + 4 x

from both sides

x^{2} + 2 x - (x^{2} + 4 x) = x^{2} + 4 x - 6 - (x^{2} + 4 x)

Simplify

- 2 x = - 6

Divide both sides by

- 2

x = 3

\frac{6 x - 8}{33} = \frac{x - 2}{3} - \frac{1 - 5 x}{6}

a, a + b = 3

5 x - 6 = 2 x + 3

\frac{3 x}{4} + \frac{2 x}{3} = \frac{17}{12}

(2 - 2 i) z = 10

What is the answer to 3^2+(x+1)^2=(x+2)^2 ?
The answer to 3^2+(x+1)^2=(x+2)^2 is x=3
Solve for x: 3^2+(x+1)^2=(x+2)^2
The solution is x=3