What is the answer to solvefor f,(f+g)(x)=f+g ?

The answer to solvefor f,(f+g)(x)=f+g is f=-g;\quad x\ne 1

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solvefor f,(f+g)(x)=f+g

solve for

f, (f + g) (x) = f + g

f = - g; x \neq = 1

Solution steps

(f + g) (x) = f + g

Expand

(f + g) (x) : x f + xg

x f + xg = f + g

Move

xg

to the right side

x f = f + g - xg

Move

f

to the left side

x f - f = g - xg

Factor

x f - f : f (x - 1)

f (x - 1) = g - xg

Divide both sides by

x - 1; x \neq = 1

f = - g; x \neq = 1

x - 2 = 10

f, s = 3 f - 24

\frac{11 ( x - 5 )}{3} + \frac{5 ( x - 8 )}{6} = \frac{4 ( 2 - x )}{7}

60 = \frac{( x )}{( 1 + 2 \times 7 )}

- 6 m = - 9 (2 m - 4)

What is the answer to solvefor f,(f+g)(x)=f+g ?
The answer to solvefor f,(f+g)(x)=f+g is f=-g;\quad x\ne 1