What is the answer to solvefor a,f=ax^2+b ?

The answer to solvefor a,f=ax^2+b is a=(f-b)/(x^2);\quad x\ne 0

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solvefor a,f=ax^2+b

solve for

a, f = a x^{2} + b

a = \frac{f - b}{x ^{2}}; x \neq = 0

Solution steps

f = a x^{2} + b

Switch sides

a x^{2} + b = f

Move

b

to the right side

a x^{2} = f - b

Divide both sides by

x^{2}; x \neq = 0

a = \frac{f - b}{x ^{2}}; x \neq = 0

11 - x = 29

7 + y = 5 (2 y - 1) + 3 y

- \frac{3}{2} f - 3 + \frac{1}{3} f = 4 + 2 f - \frac{5}{6} f

y, 3 x - 4 y = 8

\frac{x}{9} + 64 = 100

What is the answer to solvefor a,f=ax^2+b ?
The answer to solvefor a,f=ax^2+b is a=(f-b)/(x^2);\quad x\ne 0