What is the answer to x^2+4=(x+1)(x+3) ?

The answer to x^2+4=(x+1)(x+3) is x= 1/4

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x^2+4=(x+1)(x+3)

x^{2} + 4 = (x + 1) (x + 3)

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

x^{2} + 4 = (x + 1) (x + 3)

Expand

(x + 1) (x + 3) : x^{2} + 4 x + 3

x^{2} + 4 = x^{2} + 4 x + 3

Move

4

to the right side

x^{2} = x^{2} + 4 x - 1

Subtract

x^{2} + 4 x

from both sides

x^{2} - (x^{2} + 4 x) = x^{2} + 4 x - 1 - (x^{2} + 4 x)

Simplify

- 4 x = - 1

Divide both sides by

- 4

x = \frac{1}{4}

x, - 4 x + 2 y = 6

y = 2 (0) - 1

x, 8 x + 3 y = - 9

x - 75 = 130

7 x + 5 = 2 x - 15

What is the answer to x^2+4=(x+1)(x+3) ?
The answer to x^2+4=(x+1)(x+3) is x= 1/4
Solve for x: x^2+4=(x+1)(x+3)
The solution is x= 1/4