What is the answer to 12-{6x+[3x+(x-7)(x+7)]-(2x+3)^2}=-2x^2+5[(x+1)^2-3(x+6)] ?

The answer to 12-{6x+[3x+(x-7)(x+7)]-(2x+3)^2}=-2x^2+5[(x+1)^2-3(x+6)] is x=-155/8

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12-{6x+[3x+(x-7)(x+7)]-(2x+3)^2}=-2x^2+5[(x+1)^2-3(x+6)]

12 - {6 x + [3 x + (x - 7) (x + 7)] - (2 x + 3)^{2}} = - 2 x^{2} + 5 [(x + 1)^{2} - 3 (x + 6)]

x = - \frac{155}{8}

Solution steps

12 - {6 x + [3 x + (x - 7) (x + 7)] - (2 x + 3)^{2}} = - 2 x^{2} + 5 [(x + 1)^{2} - 3 (x + 6)]

Remove parentheses:

(a) = a

12 - (6 x + 3 x + (x - 7) (x + 7) - (2 x + 3)^{2}) = - 2 x^{2} + 5 [(x + 1)^{2} - 3 (x + 6)]

Add similar elements:

6 x + 3 x = 9 x

12 - (9 x + (x - 7) (x + 7) - (2 x + 3)^{2}) = - 2 x^{2} + 5 [(x + 1)^{2} - 3 (x + 6)]

Expand

12 - (9 x + (x - 7) (x + 7) - (2 x + 3)^{2}) : 3 x^{2} + 3 x + 70

Expand

- 2 x^{2} + 5 ((x + 1)^{2} - 3 (x + 6)) : 3 x^{2} - 5 x - 85

3 x^{2} + 3 x + 70 = 3 x^{2} - 5 x - 85

Move

70

to the right side

3 x^{2} + 3 x = 3 x^{2} - 5 x - 155

Subtract

3 x^{2} - 5 x

from both sides

3 x^{2} + 3 x - (3 x^{2} - 5 x) = 3 x^{2} - 5 x - 155 - (3 x^{2} - 5 x)

Simplify

8 x = - 155

Divide both sides by

8

x = - \frac{155}{8}

x, 4 x + 8 y = 20

6 - x = 5 x + 30

x, 7 x + y = 7

m - 3 \frac{2}{9} = 1 \frac{2}{3}

x, 7 x - y = 7

What is the answer to 12-{6x+[3x+(x-7)(x+7)]-(2x+3)^2}=-2x^2+5[(x+1)^2-3(x+6)] ?
The answer to 12-{6x+[3x+(x-7)(x+7)]-(2x+3)^2}=-2x^2+5[(x+1)^2-3(x+6)] is x=-155/8
Solve for x: 12-{6x+[3x+(x-7)(x+7)]-(2x+3)^2}=-2x^2+5[(x+1)^2-3(x+6)]
The solution is x=-155/8