What are the solutions to the equation x^2+9x+14=0 ?

The solutions to the equation x^2+9x+14=0 are x=-2,x=-7

Find the zeros of x^2+9x+14=0

The zeros of x^2+9x+14=0 are x=-2,x=-7

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x^{2} + 9 x + 14 = 0

x = - 2, x = - 7

Solution steps

x^{2} + 9 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 14 = 5

x_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 5}{2 \cdot 1}, x_{2} = \frac{- 9 - 5}{2 \cdot 1}

x = \frac{- 9 + 5}{2 \cdot 1} : - 2

x = \frac{- 9 - 5}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 2, x = - 7

∣ x + 3 ∣ > 14

lo g_{5} (100)

- (1 + 8 x) = - 31 - 2 x

- \frac{1}{5} (3 c - 4) = - 2 (- c - 2)

x (x + 6) = - 9

What are the solutions to the equation x^2+9x+14=0 ?
The solutions to the equation x^2+9x+14=0 are x=-2,x=-7
Find the zeros of x^2+9x+14=0
The zeros of x^2+9x+14=0 are x=-2,x=-7