What is the answer to solvefor A,y=A_{1}e^x+A_{2}e^{-2x} ?

The answer to solvefor A,y=A_{1}e^x+A_{2}e^{-2x} is True for all A;\quad y=A_{1}e^x+A_{2}e^{-2x}

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solvefor A,y=A_{1}e^x+A_{2}e^{-2x}

solve for

A, y = A_{1} e^{x} + A_{2} e^{- 2 x}

True for all A; y = A_{1} e^{x} + A_{2} e^{- 2 x}

Solution steps

y = A_{1} e^{x} + A_{2} e^{- 2 x}

Both sides are equal

True for all A; y = A_{1} e^{x} + A_{2} e^{- 2 x}

x, x + y + 3 = 0

6 x = 30

12 (p - 2 \frac{1}{3}) = - 8

x, x + y + z = 5

\frac{1}{3} (\frac{3}{4} e - 12) + 3 e = 6 - \frac{1}{2} e

What is the answer to solvefor A,y=A_{1}e^x+A_{2}e^{-2x} ?
The answer to solvefor A,y=A_{1}e^x+A_{2}e^{-2x} is True for all A;\quad y=A_{1}e^x+A_{2}e^{-2x}