What is the answer to -2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4) ?

The answer to -2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4) is y=2

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-2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4)

- 2 y - 3 - {- 4 y + 5 + [- y + 2 - (3 y - 1) + 2 y - 5]} = - (y - 4)

y = 2

Solution steps

- 2 y - 3 - {- 4 y + 5 + [- y + 2 - (3 y - 1) + 2 y - 5]} = - (y - 4)

Remove parentheses:

(- a) = - a

- 2 y - 3 - (- 4 y + 5 - y + 2 - (3 y - 1) + 2 y - 5) = - (y - 4)

Simplify

- 4 y + 5 - y + 2 - (3 y - 1) + 2 y - 5 : - 3 y - (3 y - 1) + 5 + 2 - 5

- 2 y - 3 - (- 3 y - (3 y - 1) + 5 + 2 - 5) = - (y - 4)

Expand

- 2 y - 3 - (- 3 y - (3 y - 1) + 5 + 2 - 5) : 4 y - 6

Expand

- (y - 4) : - y + 4

4 y - 6 = - y + 4

Move

6

to the right side

4 y = - y + 10

Move

y

to the left side

5 y = 10

Divide both sides by

5

y = 2

- (3 x + 8 - (- 15 + 6 x - (- 3 x + 2) - (5 x + 4)) - 29) = - 5

x, (y - 1) \frac{2}{4} - (x - 3) \frac{2}{9} = 1

x, 2 x - 3 y = - 4

f = (\frac{1}{3})^{2}

a, a + b = 1

What is the answer to -2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4) ?
The answer to -2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4) is y=2
Solve for y: -2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4)
The solution is y=2