What are the solutions to the equation (x-5)^2=-5 ?

The solutions to the equation (x-5)^2=-5 are x=sqrt(5)i+5,x=-sqrt(5)i+5

Find the zeros of (x-5)^2=-5

The zeros of (x-5)^2=-5 are x=sqrt(5)i+5,x=-sqrt(5)i+5

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(x - 5)^{2} = - 5

x = 5 i + 5, x = - 5 i + 5

Solution steps

(x - 5)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = - 5 : x = 5 i + 5

Solve

x - 5 = - - 5 : x = - 5 i + 5

The solutions to the quadratic equation are:

x = 5 i + 5, x = - 5 i + 5

2 π r = 20

- \frac{13}{30} + \frac{25}{42}

x^{4} + 2 x^{2} + 1

(\frac{5}{4})^{- 1}

(0.5)^{\frac{1}{2}}

What are the solutions to the equation (x-5)^2=-5 ?
The solutions to the equation (x-5)^2=-5 are x=sqrt(5)i+5,x=-sqrt(5)i+5
Find the zeros of (x-5)^2=-5
The zeros of (x-5)^2=-5 are x=sqrt(5)i+5,x=-sqrt(5)i+5