What is the answer to solvefor A,y=Ax^3+B ?

The answer to solvefor A,y=Ax^3+B is A=(y-B)/(x^3);\quad x\ne 0

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solvefor A,y=Ax^3+B

solve for

A, y = A x^{3} + B

A = \frac{y - B}{x ^{3}}; x \neq = 0

Solution steps

y = A x^{3} + B

Switch sides

A x^{3} + B = y

Move

B

to the right side

A x^{3} = y - B

Divide both sides by

x^{3}; x \neq = 0

A = \frac{y - B}{x ^{3}}; x \neq = 0

- 9 d - 4 d - 9 d + 9 = - 13

6 (3 - 5 w) = 5 (4 - 2 w) - 20 w

- 2 x - 4 = 0

2 n = 0.6 + 2.3 n

\frac{x}{3} + \frac{2 x}{5} - \frac{10 x}{15} = 1

What is the answer to solvefor A,y=Ax^3+B ?
The answer to solvefor A,y=Ax^3+B is A=(y-B)/(x^3);\quad x\ne 0