What is the answer to solvefor x,u=xy+yz+zx ?

The answer to solvefor x,u=xy+yz+zx is x=(u-yz)/(y+z);\quad y+z\ne 0

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solvefor x,u=xy+yz+zx

solve for

x, u = x y + yz + z x

x = \frac{u - yz}{y + z}; y + z \neq = 0

Solution steps

u = x y + yz + z x

Switch sides

x y + yz + z x = u

Move

yz

to the right side

x y + z x = u - yz

Factor

x y + z x : x (y + z)

x (y + z) = u - yz

Divide both sides by

y + z; y + z \neq = 0

x = \frac{u - yz}{y + z}; y + z \neq = 0

x, - 3 x + 2 y = 2

x, y - 6 = 4 (x + 5)

y = lo g_{2} (4)

5 - x = 0

8 y + 27 = 2 y - 3

What is the answer to solvefor x,u=xy+yz+zx ?
The answer to solvefor x,u=xy+yz+zx is x=(u-yz)/(y+z);\quad y+z\ne 0