What are the solutions to the equation 2x^2-9x=1 ?

The solutions to the equation 2x^2-9x=1 are x=(9+sqrt(89))/4 ,x=(9-sqrt(89))/4

Find the zeros of 2x^2-9x=1

The zeros of 2x^2-9x=1 are x=(9+sqrt(89))/4 ,x=(9-sqrt(89))/4

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2 x^{2} - 9 x = 1

x = \frac{9 + 89}{4}, x = \frac{9 - 89}{4}

Solution steps

2 x^{2} - 9 x = 1

Move

1

to the left side

2 x^{2} - 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 1) = 89

x_{1, 2} = \frac{- ( - 9 ) \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 89}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 89}{2 \cdot 2}

x = \frac{- ( - 9 ) + 89}{2 \cdot 2} : \frac{9 + 89}{4}

x = \frac{- ( - 9 ) - 89}{2 \cdot 2} : \frac{9 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 89}{4}, x = \frac{9 - 89}{4}

2 = 3

x^{2} + 8 x + 37 = 0

2 s - 8 = 12

27 - 9

\frac{2 + 5 i}{2 - 5 i}

What are the solutions to the equation 2x^2-9x=1 ?
The solutions to the equation 2x^2-9x=1 are x=(9+sqrt(89))/4 ,x=(9-sqrt(89))/4
Find the zeros of 2x^2-9x=1
The zeros of 2x^2-9x=1 are x=(9+sqrt(89))/4 ,x=(9-sqrt(89))/4