What is the answer to 3(2x-1)^2-(3x-2)(4x+1)=6 ?

The answer to 3(2x-1)^2-(3x-2)(4x+1)=6 is x=-1/7

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3(2x-1)^2-(3x-2)(4x+1)=6

3 (2 x - 1)^{2} - (3 x - 2) (4 x + 1) = 6

x = - \frac{1}{7}

Decimal Notation

x = - 0.14285 \dots

Solution steps

3 (2 x - 1)^{2} - (3 x - 2) (4 x + 1) = 6

Expand

3 (2 x - 1)^{2} - (3 x - 2) (4 x + 1) : - 7 x + 5

- 7 x + 5 = 6

Move

5

to the right side

- 7 x = 1

Divide both sides by

- 7

x = - \frac{1}{7}

x, x + 7 y = 17

x - 5 = 4

5 x + 4 x - 68 = 34 - 8 x

6 (y + 1.5) = - 18

\frac{4 x + 1}{5} = \frac{5 x + 8}{6}

What is the answer to 3(2x-1)^2-(3x-2)(4x+1)=6 ?
The answer to 3(2x-1)^2-(3x-2)(4x+1)=6 is x=-1/7
Solve for x: 3(2x-1)^2-(3x-2)(4x+1)=6
The solution is x=-1/7