What are the solutions to the equation 8y^2+22y+15=0 ?

The solutions to the equation 8y^2+22y+15=0 are y=-5/4 ,y=-3/2

Find the zeros of 8y^2+22y+15=0

The zeros of 8y^2+22y+15=0 are y=-5/4 ,y=-3/2

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8 y^{2} + 22 y + 15 = 0

y = - \frac{5}{4}, y = - \frac{3}{2}

Solution steps

8 y^{2} + 22 y + 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 8 \cdot 15}{2 \cdot 8}

2 2^{2} - 4 \cdot 8 \cdot 15 = 2

y_{1, 2} = \frac{- 22 \pm 2}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- 22 + 2}{2 \cdot 8}, y_{2} = \frac{- 22 - 2}{2 \cdot 8}

y = \frac{- 22 + 2}{2 \cdot 8} : - \frac{5}{4}

y = \frac{- 22 - 2}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

y = - \frac{5}{4}, y = - \frac{3}{2}

- 11 - 5 a = 6 (5 a + 4)

(0.2 + x) (0.1 + x) = x

(x^{- \frac{1}{3}})^{2}

\frac{1}{2} \cdot \frac{1}{6} \cdot \frac{1}{2}

\frac{10 x - 5}{2 x - 4} < 0

What are the solutions to the equation 8y^2+22y+15=0 ?
The solutions to the equation 8y^2+22y+15=0 are y=-5/4 ,y=-3/2
Find the zeros of 8y^2+22y+15=0
The zeros of 8y^2+22y+15=0 are y=-5/4 ,y=-3/2