What is the answer to (x-1)/2+(x-2)/3 =(x-3)/4+(x-4)/5 ?

The answer to (x-1)/2+(x-2)/3 =(x-3)/4+(x-4)/5 is x=-1

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(x-1)/2+(x-2)/3 =(x-3)/4+(x-4)/5

\frac{x - 1}{2} + \frac{x - 2}{3} = \frac{x - 3}{4} + \frac{x - 4}{5}

x = - 1

Solution steps

\frac{x - 1}{2} + \frac{x - 2}{3} = \frac{x - 3}{4} + \frac{x - 4}{5}

Multiply by LCM

30 (x - 1) + 20 (x - 2) = 15 (x - 3) + 12 (x - 4)

Expand

30 (x - 1) + 20 (x - 2) : 50 x - 70

Expand

15 (x - 3) + 12 (x - 4) : 27 x - 93

50 x - 70 = 27 x - 93

Move

70

to the right side

50 x = 27 x - 23

Move

27 x

to the left side

23 x = - 23

Divide both sides by

23

x = - 1

x, 5 x + y = - 4

2 (- 6 m - 3) = 6 (5 m - 1)

x, y - 3 x = 5

y, x = 1 + y

4 x + 6 = 0

What is the answer to (x-1)/2+(x-2)/3 =(x-3)/4+(x-4)/5 ?
The answer to (x-1)/2+(x-2)/3 =(x-3)/4+(x-4)/5 is x=-1
Solve for x: (x-1)/2+(x-2)/3 =(x-3)/4+(x-4)/5
The solution is x=-1