What is the answer to solvefor a,(4x-1)=(3pi)/(20)rad ?

The answer to solvefor a,(4x-1)=(3pi)/(20)rad is a=(20(4x-1))/(3pidr);\quad 3pidr\ne 0

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solvefor a,(4x-1)=(3pi)/(20)rad

solve for

a, (4 x - 1)^{\circ} = \frac{3 π}{20} r a d

a = \frac{20 ( 4 x - 1 ) ^{\circ}}{3 π d r}; 3 π d r \neq = 0

Solution steps

(4 x - 1)^{\circ} = \frac{3 π}{20} r a d

Switch sides

\frac{3 π}{20} r a d = (4 x - 1)^{\circ}

Multiply both sides by

20

3 πa d r = 20 (4 x - 1)^{\circ}

Divide both sides by

3 π d r; 3 π d r \neq = 0

a = \frac{20 ( 4 x - 1 ) ^{\circ}}{3 π d r}; 3 π d r \neq = 0

2 (x - 3) = - 3 x + 4

\frac{x}{2} = 0

\frac{x}{5} = 1

x, y - 4 = 3 (x - 2)

s, 2 x - 1 = sin (x)

What is the answer to solvefor a,(4x-1)=(3pi)/(20)rad ?
The answer to solvefor a,(4x-1)=(3pi)/(20)rad is a=(20(4x-1))/(3pidr);\quad 3pidr\ne 0