What are the solutions to the equation 4x^2-5x-7=0 ?

The solutions to the equation 4x^2-5x-7=0 are x=(5+sqrt(137))/8 ,x=(5-sqrt(137))/8

Find the zeros of 4x^2-5x-7=0

The zeros of 4x^2-5x-7=0 are x=(5+sqrt(137))/8 ,x=(5-sqrt(137))/8

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4 x^{2} - 5 x - 7 = 0

x = \frac{5 + 137}{8}, x = \frac{5 - 137}{8}

Decimal Notation

x = 2.08808 \dots, x = - 0.83808 \dots

Solution steps

4 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 7) = 137

x_{1, 2} = \frac{- ( - 5 ) \pm 137}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 137}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 137}{2 \cdot 4}

x = \frac{- ( - 5 ) + 137}{2 \cdot 4} : \frac{5 + 137}{8}

x = \frac{- ( - 5 ) - 137}{2 \cdot 4} : \frac{5 - 137}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 137}{8}, x = \frac{5 - 137}{8}

11 - 4 p \leq - 9

4 (6 x - 1)^{2} - 5 = 223

\frac{1}{16} - 1

30 x^{3} y + 35 x^{2} y^{2}

x + 23 = 9 x - 17

What are the solutions to the equation 4x^2-5x-7=0 ?
The solutions to the equation 4x^2-5x-7=0 are x=(5+sqrt(137))/8 ,x=(5-sqrt(137))/8
Find the zeros of 4x^2-5x-7=0
The zeros of 4x^2-5x-7=0 are x=(5+sqrt(137))/8 ,x=(5-sqrt(137))/8