What are the solutions to the equation 48x^2-8=2x-22 ?

The solutions to the equation 48x^2-8=2x-22 are x= 1/48+i(sqrt(671))/(48),x= 1/48-i(sqrt(671))/(48)

Find the zeros of 48x^2-8=2x-22

The zeros of 48x^2-8=2x-22 are x= 1/48+i(sqrt(671))/(48),x= 1/48-i(sqrt(671))/(48)

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48 x^{2} - 8 = 2 x - 22

x = \frac{1}{48} + i \frac{671}{48}, x = \frac{1}{48} - i \frac{671}{48}

Solution steps

48 x^{2} - 8 = 2 x - 22

Move

22

to the left side

48 x^{2} + 14 = 2 x

Move

2 x

to the left side

48 x^{2} + 14 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

48 x^{2} - 2 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 48 \cdot 14}{2 \cdot 48}

Simplify

(- 2)^{2} - 4 \cdot 48 \cdot 14 : 2671 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 671 i}{2 \cdot 48}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 671 i}{2 \cdot 48}, x_{2} = \frac{- ( - 2 ) - 2 671 i}{2 \cdot 48}

x = \frac{- ( - 2 ) + 2 671 i}{2 \cdot 48} : \frac{1}{48} + i \frac{671}{48}

x = \frac{- ( - 2 ) - 2 671 i}{2 \cdot 48} : \frac{1}{48} - i \frac{671}{48}

The solutions to the quadratic equation are:

x = \frac{1}{48} + i \frac{671}{48}, x = \frac{1}{48} - i \frac{671}{48}

- 4 + \frac{5}{3}

\frac{13}{5} - (\frac{1}{2} + \frac{1}{6})

2 x^{2} - 7 x + 5 < 0

- 3 - 5

12 x = - 4 (2 x - 5)

What are the solutions to the equation 48x^2-8=2x-22 ?
The solutions to the equation 48x^2-8=2x-22 are x= 1/48+i(sqrt(671))/(48),x= 1/48-i(sqrt(671))/(48)
Find the zeros of 48x^2-8=2x-22
The zeros of 48x^2-8=2x-22 are x= 1/48+i(sqrt(671))/(48),x= 1/48-i(sqrt(671))/(48)