What is the answer to (x-(2x-5))/7 =(2-(3x+2))/3 ?

The answer to (x-(2x-5))/7 =(2-(3x+2))/3 is x=-5/6

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(x-(2x-5))/7 =(2-(3x+2))/3

\frac{x - ( 2 x - 5 )}{7} = \frac{2 - ( 3 x + 2 )}{3}

x = - \frac{5}{6}

Decimal Notation

x = - 0.83333 \dots

Solution steps

\frac{x - ( 2 x - 5 )}{7} = \frac{2 - ( 3 x + 2 )}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(x - (2 x - 5)) \cdot 3 = 7 (2 - (3 x + 2))

Simplify

3 (- x + 5) = - 21 x

Expand

3 (- x + 5) : - 3 x + 15

- 3 x + 15 = - 21 x

Move

15

to the right side

- 3 x = - 21 x - 15

Move

21 x

to the left side

18 x = - 15

Divide both sides by

18

x = - \frac{5}{6}

x, x + 3 y - 6 = 0

b - 9 + 6 b = 30

5 x + 18 - 8 x = 33

53 = \frac{7}{10} c + 11

6 x - 2 = - 14

What is the answer to (x-(2x-5))/7 =(2-(3x+2))/3 ?
The answer to (x-(2x-5))/7 =(2-(3x+2))/3 is x=-5/6
Solve for x: (x-(2x-5))/7 =(2-(3x+2))/3
The solution is x=-5/6