What is the answer to solvefor a,y=ax^2+b ?

The answer to solvefor a,y=ax^2+b is a=(y-b)/(x^2);\quad x\ne 0

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solvefor a,y=ax^2+b

solve for

a, y = a x^{2} + b

a = \frac{y - b}{x ^{2}}; x \neq = 0

Solution steps

y = a x^{2} + b

Switch sides

a x^{2} + b = y

Move

b

to the right side

a x^{2} = y - b

Divide both sides by

x^{2}; x \neq = 0

a = \frac{y - b}{x ^{2}}; x \neq = 0

x, y - 2 = 2 (x + 3)

- 3 x = 3

x, 3 y = 2 x

3 (2 x - 4) + 3 (x + 1) = 9

4 y = 12

What is the answer to solvefor a,y=ax^2+b ?
The answer to solvefor a,y=ax^2+b is a=(y-b)/(x^2);\quad x\ne 0