What are the solutions to the equation x^2-7x-8=0 ?

The solutions to the equation x^2-7x-8=0 are x=8,x=-1

Find the zeros of x^2-7x-8=0

The zeros of x^2-7x-8=0 are x=8,x=-1

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x^{2} - 7 x - 8 = 0

x = 8, x = - 1

Solution steps

x^{2} - 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

x = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

x = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 8, x = - 1

x^{2} - x - \frac{3}{2} = 0

e^{x} \cdot e^{- y}

4 \cdot (\frac{1}{2})^{- 2 - 1} - 2

\frac{7}{3 - 2}

\frac{0.02 \cdot 0.1}{0.05}

What are the solutions to the equation x^2-7x-8=0 ?
The solutions to the equation x^2-7x-8=0 are x=8,x=-1
Find the zeros of x^2-7x-8=0
The zeros of x^2-7x-8=0 are x=8,x=-1