What is the answer to solvefor a,y=at^5-5bt^3 ?

The answer to solvefor a,y=at^5-5bt^3 is a=(y+5bt^3)/(t^5);\quad t\ne 0

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solvefor a,y=at^5-5bt^3

solve for

a, y = a t^{5} - 5 b t^{3}

a = \frac{y + 5 b t ^{3}}{t ^{5}}; t \neq = 0

Solution steps

y = a t^{5} - 5 b t^{3}

Switch sides

a t^{5} - 5 b t^{3} = y

Move

5 b t^{3}

to the right side

a t^{5} = y + 5 b t^{3}

Divide both sides by

t^{5}; t \neq = 0

a = \frac{y + 5 b t ^{3}}{t ^{5}}; t \neq = 0

x, 4 x - 5 y = 40

x, x - 2 y + 4 = 0

lo g_{3} (27) = 3 n + 6

5 x = - 15

y, 5 x - 2 y = 10

What is the answer to solvefor a,y=at^5-5bt^3 ?
The answer to solvefor a,y=at^5-5bt^3 is a=(y+5bt^3)/(t^5);\quad t\ne 0